什么时候需要C ++中的私有构造函数? [英] When do we need a private constructor in C++?

问题描述

我对C ++中的私有构造函数有疑问.如果构造函数是私有的，该如何创建该类的实例?

I have a question about private constructors in C++. If the constructor is private, how can I create an instance of the class?

我们应该在类内部使用getInstance()方法吗?

Should we have a getInstance() method inside the class?

推荐答案

在某些情况下，可以使用 private 构造函数:

There are a few scenarios for having private constructors:

1. 限制除 friend 以外的所有对象的对象创建；在这种情况下，所有构造函数都必须是 private

1. Restricting object creation for all but friends; in this case all constructors have to be private

class A
{
private:
   A () {}
public:
   // other accessible methods
   friend class B;
};

class B
{
public:
   A* Create_A () { return new A; }  // creation rights only with `B`
};

限制某些类型的构造函数(即复制构造函数，默认构造函数).例如 std :: fstream 不允许通过此类无法访问的构造函数进行复制

Restricting certain type of constructor (i.e. copy constructor, default constructor). e.g. std::fstream doesn't allow copying by such inaccessible constructor

class A
{
public:
   A();
   A(int);
private:
   A(const A&);  // C++03: Even `friend`s can't use this
   A(const A&) = delete;  // C++11: making `private` doesn't matter
};

要有一个公共的委托构造函数，而该构造函数不应暴露给外部世界:

To have a common delegate constructor, which is not supposed to be exposed to the outer world:

class A
{
private: 
  int x_;
  A (const int x) : x_(x) {} // common delegate; but within limits of `A`
public:
  A (const B& b) : A(b.x_) {}
  A (const C& c) : A(c.foo()) {}
};

对于单例模式，当单例 class 是不可继承的(如果它是可继承的，然后使用受保护的构造函数)

For singleton patterns when the singleton class is not inheritible (if it's inheritible then use a protected constructor)

class Singleton
{
public:
   static Singleton& getInstance() {
      Singleton object; // lazy initialization or use `new` & null-check
      return object;
   }
private:
   Singleton() {}  // make `protected` for further inheritance
   Singleton(const Singleton&);  // inaccessible
   Singleton& operator=(const Singleton&);  // inaccessible
};

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