错误:将限定符放在类型x的绑定引用与类型y的初始化程序中 [英] Error: Qualifiers dropped in binding reference of type x to initializer of type y

问题描述

以下原因为何引发此错误:

why does the following throw this error:

IntelliSense:限定符已放入类型的绑定引用中字符串和"到常量字符串"类型的初始化程序

IntelliSense: qualifiers dropped in binding reference of type "string &" to initializer of type "const string"

.h

class A
{
public:
    wstring& GetTitle() const;
private:
    wstring title;    
};

.cpp

wstring& GetTitle() const
{
    return this->title;
}

如果我删除了const字，它会停止抱怨，但是我从未对变量进行过任何更改吗?

If i remove the const word, it stops complaining, and yet i have never made any changes to the variable?

推荐答案

通过返回对类成员的非常量引用，您可以使调用者访问该对象，就好像它是非常量一样.但是 GetTitle 作为const函数，无权授予该访问权限.

By returning a non-const reference to a member of your class, you are giving the caller access to the object as if it's non const. But GetTitle, being a const function, does not have the right to grant that access.

例如:

A a;
string& b = a.GetTitle(); // Allows control over original variable

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