比较wstring和忽略大小写 [英] Comparing wstring with ignoring the case

问题描述

我敢肯定这会在之前被问到，但找不到.是否有任何内置方式(即使用std :: wstring的方法或算法)对两个wstring对象进行不区分大小写的比较?

I am sure this would have been asked before but couldn't find it. Is there any built in (i.e. either using std::wstring's methods or the algorithms) way to case insensitive comparison the two wstring objects?

推荐答案

如果您不介意与Microsoft实现绑定，则可以使用在< string.h> 中定义的此函数>

If you don't mind being tied to Microsoft implementation you can use this function defined in <string.h>

int _wcsnicmp(
   const wchar_t *string1,
   const wchar_t *string2,
   size_t count 
);

但是，如果您想要最佳的性能/兼容性/功能比，则可能需要查看boost库(无论如何它都是stl).简单示例(取自针对不同问题的不同答案):

But if you want best performance/compatibility/functionality ratio you will probably have to look at boost library (part of it is stl anyway). Simple example (taken from different answer to different question):

#include <boost/algorithm/string.hpp>

std::wstring wstr1 = L"hello, world!";
std::wstring wstr2 = L"HELLO, WORLD!";

if (boost::iequals(wstr1, wstr2))
{
    // Strings are identical
}

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