如何在C ++中替换向量中的特定值? [英] How to replace specific values in a vector in C++?

问题描述

我有一个带有某些值(3、3、6、4、9、6、1、4、6、6、7、3)的向量，我想用54替换每个3或用54替换每个6例如1，依此类推.

I have a vector with some values (3, 3, 6, 4, 9, 6, 1, 4, 6, 6, 7, 3), and I want to replace each 3 with a 54 or each 6 with a 1, for example and so on.

因此，我需要先遍历向量，获取[i]值，搜索并用54替换每个3，但仍要保留相关的 positions.std :: set vector :: swap 是一个好方法吗?我什至不知道该如何开始:(我不能使用 push_back ，因为那样就不能保持正确的值顺序，这很重要.

So I need to go through the vector first, get the [i] value, search and replace each 3 with a 54, but still keep relevant positions.std::set is vector::swap a good way? I am not even sure how to begin this :( I can't use push_back as that would not keep the correct order of values as that is important.

请保持简单；我只是一个初学者:)

Please keep it simple; I am just a beginner :)

推荐答案

作业的工具是 std :: replace :

The tool for the job is std::replace:

std::vector<int> vec { 3, 3, 6, /* ... */ };
std::replace(vec.begin(), vec.end(), 3, 54); // replaces in-place

查看实际效果 .

See it in action.

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