为什么我要“使用已删除"?函数传递std :: ofstream作为参数时的功能? [英] Why do I make "use of deleted" function when passing a std::ofstream as parameter?

问题描述

我有一个成员，该成员是 std :: ofstream fBinaryFile 和一个

I have a member that is std::ofstream fBinaryFile and a

void setFile( std::ofstream& pBinaryFile ) 
{
    fBinaryFile = pBinaryFile;
}

输出:

 Data.h:86:16: error: use of deleted function ‘std::basic_ofstream<char>& std::basic_ofstream<char>::operator=(const
 std::basic_ofstream<char>&)’
     fBinaryFile = pBinaryFile;
                 ^

我了解到不允许在 std :: ofstream 中进行复制，也许我缺少了一些东西.可以将 pBinaryFile 的内容保存在 fBinaryfile 中吗?

I understood that copy in std::ofstream is not allowed and maybe I'm missing something. Is possible save the content of pBinaryFile in fBinaryfile?

推荐答案

因为相关的运算符被声明为

Because the relevant operator is declared as

ofstream& operator= (const ofstream&) = delete;

这意味着它被明确禁止，因此 ofstream 语义确实支持复制.

which means it is explicitly prohibited so ofstream semantics does to support copying.

根据您的体系结构，您可以存储指针/引用或将其移动.

Depending on your architecture you can store a pointer/reference or move it.

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