函数隐藏和重载之间的区别 [英] difference between function hiding and overloading

问题描述

我找不到函数隐藏和重载之间的任何区别.由于函数隐藏是存在于派生类中的函数，并且隐藏了基类的函数.它们在两个函数中具有相同的名称.重载:在派生类和基类中具有相同的名称，但签名不同.

I can't find any difference between function hiding and overloading. As the function hiding is the function that is present in derived class and hides the function of a base class. Having same name of the function in both of them. Overloading: having same name but different signature in both derived and base class.

class A {
    void print(int);
};
class B: public A {
    void print(float);
};

它是隐藏功能还是重载?

does it hide function or overload ?

推荐答案

函数 B :: print 隐藏父函数 A :: print .

如果要重载，则需要将 A :: print 函数拉入 B 的范围:

If you want to overload you need to pull in the A::print function into the scope of B:

class B : public A {
public:
    using A::print;  // Pull in (all) A::print symbols into the scope of B

    void print(float);  // Now overloads A::print
};

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