Qt Creator没有名为stackedWidget的成员 [英] Qt Creator no member named stackedWidget

问题描述

我刚刚在QT-Creator中设计了自己的ui，由于主应用程序基于两个面板，所以我决定使用StackedWidget来更改布局"，而无需打开新窗口.

I've just designed my ui in the QT-Creator and, as the main application is based on two panels, I decided to use the StackedWidget for "change the layout" without opening a new window.

因此，我添加了一个名为:stackedWidget(默认)的QTStackedWidget.

So, I added a QTStackedWidget named: stackedWidget (as default).

问题出在mainwindow.cpp中，我添加了一个包含以下内容的自定义SLOT:

The problem is in mainwindow.cpp, I added a custom SLOT that contain:

ui->stackedWidget->setCurrentIndex(1);

在构建此文件时，编译器会说:

when I build this the compiler says:

mainwindow.cpp:25:错误:'Ui :: MainWindow'中没有名为'stackedWidget'的成员
ui-> stackedWidget-> setCurrentIndex(1);
~~ ^

mainwindow.cpp:25: error: no member named 'stackedWidget' in 'Ui::MainWindow'
ui->stackedWidget->setCurrentIndex(1);
~~ ^

在qt-creator本身中，我也无法将信号附加到stackedWidget，因为它没有向我显示setCurrentIndex SLOT ...

also in the qt-creator itself I was unable to attach a signal to the stackedWidget because it doesn't show to me the setCurrentIndex SLOT...

有什么建议吗?

请注意，我是C ++的新手，几年前我刚刚在PyQt4中使用Qt.

Please note that I'm a noob with C++ I just used Qt a couple of years ago with PyQt4.

mainwindow.h:

mainwindow.h:

#ifndef MAINWINDOW_H
#define MAINWINDOW_H

#include <QMainWindow>

namespace Ui {
class MainWindow;
}

class MainWindow : public QMainWindow
{
    Q_OBJECT

public:
    explicit MainWindow(QWidget *parent = 0);
    ~MainWindow();

private:
    Ui::MainWindow *ui;

private slots:
    void showOtherPage();
    void showMainPage();
};

#endif // MAINWINDOW_H

mainiwindow.cpp:

mainiwindow.cpp:

#include "mainwindow.h"
#include "ui_mainwindow.h"
#include <QTimer>
#include <QDebug>

MainWindow::MainWindow(QWidget *parent) :
    QMainWindow(parent),
    ui(new Ui::MainWindow)
{
    ui->setupUi(this);
    qDebug() << "MainWindow - Debug Mode ON";
    connect(ui->btnOther, SIGNAL(clicked()), SLOT(showOtherPage()));
}

void MainWindow::showOtherPage()
{
    qDebug() << "Showing Other Page";
    ui->stackedWidget->setCurrentIndex(1);
}

void MainWindow::showMainPage()
{
    qDebug() << "Showing Main Page";
    ui->stackedWidget->setCurrentIndex(0);
}


MainWindow::~MainWindow()
{
    delete ui;
}

推荐答案

我有一个非常相似的问题.UI动作之一被定义为其他动作并被使用.我有一个 ui，没有对此成员的名为xyz 的编译错误，没有可能的解释.

I had a very similar issue. One of the UI actions was defined as the others and used. I had a ui has no member named xyz compilation error for this one only, without possible explanation.

我可以通过取消/选中项目编译选项中的 Shadow build 选项来解决该问题！

I could solve it by unchecking/checking the Shadow build option in the project compilation options!

希望这样可以节省别人30分钟，我只是失去了:)

Hope it saves someone the 30 minutes I just lost :)

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