dynamic_cast中的类型必须是指向完整类类型的指针或引用，或者为void * [英] The type in a dynamic_cast must be a pointer or reference to a complete class type, or void *

问题描述

我希望外面有人能理解下面的代码为什么失败.我正在尝试从osg :: Node *节点对象获取PositionAttitudeTransform(Openscenegraph类)的实例.但是下面以粗体显示了编译器错误.

I am hoping there is someone out there who understands why the code below fails. I am trying to get an instance of PositionAttitudeTransform (Openscenegraph class) from an osg::Node* node object. But there is the compiler error below in bold.

 void CameraPosCallbackUpdate::operator()(osg::Node* node, osg::NodeVisitor* nv)
{ 
   // other code goes here

    osg::PositionAttitudeTransform* pat = dynamic_cast<osg::PositionAttitudeTransform*> (node);

}

IntelliSense:dynamic_cast中的类型必须是指向完整类类型的指针或引用，或者为空*

请帮助我以正确的方式访问我的对象，希望能帮助我理解这里的问题，因为我相信强制转换是可能的.

Please help me with correct way to access my object and I would appreciate help in understanding what the problem here is since I believe the cast should be possible.

http://www.openscenegraph.org/documentation/OpenSceneGraphReferenceDocs/a00529.html

推荐答案

我相信您必须 #include 头文件，该头文件包含 class osg :: PositionAttitudeTransform 的正文>.
当目标类的正文不可见时， dynamic_cast 会给出此类错误.

I believe you have to #include the header file which contains the body of class osg::PositionAttitudeTransform.
dynamic_cast gives such error when the body of the destination class is not visible.

以下是类似的在g ++中再现的错误.

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