具有所有私人成员的班级可以成为POD班级吗? [英] Can a class with all private members be a POD class?

问题描述

我之前听说过POD类型不能拥有私有数据-但根据C ++ 0x草案，我的要求是宽松的(强调我的意思):

I've heard before that POD types cannot have private data -- but according to the C++0x draft I have the requirement is looser (emphasis mine):

对所有非静态数据成员具有相同的访问控制(第11条)

这似乎表明只要所有数据都是私有的，私有数据就可以.我没有C ++ 03的副本，但是要检查...

which seems to suggest that private data is okay so long as it's all private. I don't have a copy of C++03 though to check...

然后， WindowsApi :: Uuid 是POD类吗?

namespace WindowsApi
{
    class Uuid
    {
        union
        {
            ::UUID asUuid; //Win32's UUID struct
            unsigned __int64 asInt64s[2];
            unsigned __int32 asInt32s[4];
        };
    public:
        Uuid() {}
        Uuid(::UUID sourceStructure) : asUuid(sourceStructure) {}
        operator ::UUID() { return asUuid; }
    };
}

推荐答案

C ++ 03仍然不允许POD类中的非静态私有数据或受保护的数据.在 aggregate

C++03 still does not allow non-static private or protected data in POD classes. This requirement is specified in the definition of aggregate

集合是没有用户声明的构造函数(12.1)，没有私有或受保护的非静态数据成员(第11条)，没有基类(第10条)，并且没有虚函数(10.3).

An aggregate is an array or a class (clause 9) with no user-declared constructors (12.1), no private or protected non-static data members (clause 11), no base classes (clause 10), and no virtual functions (10.3).

和POD类必须首先是集合.

and POD class must be an aggregate first.

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