我如何在再次打开应用程序时显示应用程序Qt [英] How I show application when open application again Qt

问题描述

现在，我有1个应用程序，但是我不想两次打开应用程序，因此我使用 QShareMemory 来检测两次打开的应用程序.我的问题是:当用户第二次打开应用程序时，如何在屏幕上显示当前应用程序?

Now, I have 1 application, but I don't want to open application twice, so I using QShareMemory to detect application when open twice. And my question is: how I show current application in screen when user open application the second ?

int main(int argc, char *argv[]) {
    Application a(argc, argv);

    /*Make sure only one instance of application can run on host system at a time*/
    QSharedMemory sharedMemory;
    sharedMemory.setKey ("Application");
    if (!sharedMemory.create(1))
    {

        qDebug() << "123123Exit already a process running";
        return 0;

    }
    /**/

    return a.exec();
}

谢谢.

推荐答案

只需使用 QSingleApplication 类而不是 QApplication : https://github.com/qtproject/qt-solutions/tree/master/qtsingleapplication

int main(int argc, char **argv)
{
    QtSingleApplication app(argc, argv);
    if (app.isRunning())
        return 0;

    MyMainWidget mmw;
    app.setActivationWindow(&mmw);
    mmw.show();

    return app.exec();
}

它是Qt Solutions的一部分: https://github.com/qtproject/qt-solutions

It is part of Qt Solutions: https://github.com/qtproject/qt-solutions

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