C ++是否具有标准的编译时类型容器? [英] Does C++ have a standard, compile-time type container?

问题描述

((此问题的答案是

(This question has an answer by Nim which mentions boost::mpl::map.)

标准C ++中是否有一个可以容纳类型的编译时容器?

Is there a compile-time container in standard C++ which can hold types?

一个用法示例为:

compiler::vector foo{char, short, long, long long};

template <int N>
void bar(foo[N] param){/*do something and return foo[N]*/}

推荐答案

此版本位于Bérenger"的答案，这使我进入了 tuple 概念.但是我相信我们可以做得更好，甚至保留参考文献:

This build's on Bérenger's answer, which put me onto the tuple concept. But I believe we can do better, even preserving references:

tuple foo<char&, short&, long&, long long&>;

template <int N>
void bar(tuple_element_t<N, decltype(foo)> param){}

实际上，如果没有计划在此功能之外使用 foo ，我们甚至可以内联声明它:

In fact if there are no plans to use foo beyond this function we can even declare it inline:

template <int N>
void bar(tuple_element_t<N, tuple<char&, short&, long&, long long&>> param){}

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