C ++读取带空格的字符串 [英] C++ read string with spaces

问题描述

我有这样的文件:

59 137 New York
137 362 Syracuse
216 131 New Jersey
...
..
.

，我想将其读取为一个结构:X-Y-城市名称

and I would like to read it to a structure: X - Y - name of a city

  char city[100];
  int x , y;
  f.open("map.txt");
  f >> x >> y >> city;
  while (!f.fail()) {
    f >> x >> y >> city;
  }
  f.close();

问题是，该城市只读取下一个空格，因此从纽约开始，它只读取New.我应该如何以一种简单而又聪明的方式阅读一行的其余部分?

Problem is, that city reads only until next space, so from New York it reads only New. How should I read whole rest of a line, in some easy and smart way ?

推荐答案

文件格式似乎暗示城市的名称以行的结尾结尾，而不是>空格.

The format of your file seems to imply that the name of the city ends at the end of a line, not a space.

您可以使用 getline 阅读该表格a>

You can read that form using getline

  char city[100];
  int x , y;
  f.open("map.txt");
  while ( f ) {
      f >> x >> y;         
      f.getline(city, 100); 
  }
  f.close();

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