如何使用cin实现单行整数类型命令行输入验证? [英] How do I implement single line integer type command line input validation using cin?
问题描述
我有一个程序,要求用户输入[0,2]范围内的整数.我使用以下链接作为指南.
I have a program which asks the user to input an integer in the range [0,2]. I used the following link as a guide.
但是,当用户在不输入数据的情况下按Enter键时,光标仅会跳至命令提示符下的下一行,而我希望它提示用户输入有效数字.在这种情况下提示用户是否有意义,还是有理由不将验证作为开始的单行输入来实现?在使用字符串的情况下,我将使用getline解决此问题,在这种情况下,是否应该以某种方式使用它?这是我的代码,基于上面的链接:
However, when the user presses enter without inputting data the cursor simply goes to the next line in the command prompt whereas I would prefer it to prompt the user to enter a valid number. Does prompting the user in this case make sense, or is there a reason not to implement validation as single line input to begin with? In the case of strings I would use getline to solve this, should I use that somehow in this case? Here is my code, based on the above link:
#include <iostream>
int main()
{
int answeredNumber;
while(1)
{
std::cout << "Enter your answer: ";
if(std::cin >> answeredNumber && answeredNumber >= 0 && answeredNumber <= 2)
{
break;
}
else
{
std::cout << "Please enter a valid answer: " ;
std::cin.clear();
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
}
}
system("pause");
}
推荐答案
这是因为使用 cin
获取整数会跳过前导空格,其中包括换行符.没有简单的方法可以解决这个问题.
That's because getting an integer with cin
will skip leading whitespace, including a newline. There's no easy way around that.
如果要基于行的输入,则可以将输入值作为 string 来获取,然后解释为:
If you want line-based input, you can get your input value as a string and then interpret that:
#include <iostream>
#include <sstream>
#include <string>
int main (void) {
std::string inputLine;
int answer;
std::cout << "Enter your answer: ";
while(1) {
getline (std::cin, inputLine);
std::stringstream ss (inputLine);
if ((ss >> answer))
if ((answer >= 0) && (answer <= 2))
break;
std::cout << "No, please enter a VALID answer: " ;
}
std::cout << "You entered " << answer << '\n';
return 0;
}
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