C ++整数除法 [英] c++ integer division

问题描述

说我有

SDL_Rect rect;
rect.x = 5; // rect.x is of type "Uint16"
int y = 11;

我想执行 rect.x/y .

我想将结果作为浮点数，然后四舍五入到最接近的 int .

I want to get the result as a floating point number and then round up to the nearest int.

类似这样的东西:

float result = rect.x/y;
int rounded = ceil(result);

我应该怎么做?

推荐答案

投射 rect.x 或 y 浮动，然后进行除法.这将迫使整个除法运算在浮点中进行.

Cast either rect.x or y to float, and then do the division. This will force the entire division operation to take place in floating point.

float result = rect.x/(float)y;
int rounded = ceil(result);

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