从未来获取价值时的SIGABRT [英] SIGABRT when retrieving value from future

问题描述

我在使用C ++ 11期货时遇到问题.当我在 std :: async 返回的将来调用 wait()或 get()时，程序接收到 mutex 标头.可能是什么问题呢?如何解决?

I have a problem using C++11 futures. When I call wait() or get() on the future returned by std::async, the program receives SIGABRT signal thrown from the mutex header. What could be the problem? How to fix it?

我在Linux上使用g ++ 4.6.将以下代码粘贴到ideone.com会导致相同的问题.

I use g++ 4.6 on Linux. Pasting the following code to ideone.com causes the same problem.

#include <future>
#include <thread>

int calculate() {
    return 1;
}

int main() {
    auto result = std::async(calculate);
    result.wait();// <-- this aborts
    int value = result.get();// <-- or this aborts as well if previous line is commented out.

    return 0;
}

推荐答案

可以通过将 -pthread 开关添加到 g ++ 来解决该问题.

The problem may be solved by adding -pthread switch to g++.

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