Python更改__init__中声明的变量值 [英] Python changing variable values declared in __init__

问题描述

我很犹豫地问这个问题，但我的头似乎无法绕过 class ， __ init __()和 str 的使用.希望某人有足够的耐心回答可能是一个非常愚蠢的问题.我写了以下内容以测试我的理解(= 0)"

I hesitate to ask this question, but my head cannot seem to get around the use of class, __init__(), and str. Hoping that someone will be patient enough to answer what is probably a very dumb question. I have written the following to test my understanding ( = 0)"

class Test():
    def __init__(self,var1,var2):
        self.__var1 = var1
        self.__var2 = var2
    def change_var1(self):
        self.__var1
        self.__var1 =2*self.__var1
        return self.__var1, self.__var2
    def change_var2(self):
        self.__var2
        self.__var2 = self.__var2*2
        return self.__var1, self.__var2
    def __repr__(self):
        return "var1 is {}, and var 2 = {}".format(self.__var1, self.__var2)

t = Test(4,"Bye")
print(t.change_var1 )  
print(t.change_var2)

我无法在 init 中声明的变量由后续函数更改.我假设我错误地使用了类 init str__.运行上面的命令的响应是:

I cannot get the variables declared in init to be changed by the subsequent functions. I assume that I have used class, init, str__ incorrectly. The response to running what I have above is:

<bound method Test.change_var1 of var1 is 4, and var 2 = Bye>
<bound method Test.change_var2 of var1 is 4, and var 2 = Bye>

感谢您的帮助，将其推送到可以穿越我的脑海的地方！

Grateful for any help, push to a site that will get through the brick wall of my mind!!

推荐答案

执行 print(t.change_var1)时，您不是调用 change_var1功能，您只是引用.它没有被调用，因此实际上没有任何作用.

When you do print(t.change_var1), you are not calling the change_var1 function, you are merely referencing it. It is not getting called, so it doesn't actually do anything.

要调用它，您需要添加括号:

To call it you need to append parentheses:

print(t.change_var1())
print(t.change_var2())

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