我可以在Swift中使用运算符作为默认函数参数吗? [英] Can I use an operator as default function argument in Swift?

问题描述

我正在尝试使用运算符> 作为默认函数参数:

I'm trying to use operator > as default function argument:

Playground execution failed: error: StackSorting.playground:27:63: 
error: expected expression after unary operator
func sort<T>(..., compare: (T, T) -> Bool = >) where T: Comparable { }
                                            ^

我解决了，但是...有人知道一个简短的方法吗?

I solved it, but... Does somebody know a shorter way?

func sort<T>(..., compare: (T, T) -> Bool = { $0 > $1 }) where T: Comparable { }

推荐答案

您可以将运算符用作参数的默认值，您只需将其括在括号中即可:

You can use the operator as default value for the parameter, you only have to enclose it in parentheses:

func sort<T>(..., compare: (T, T) -> Bool = (>)) where T: Comparable { }

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