透视矩阵的旋转角度 [英] rotation angle of the perspective matrix

问题描述

如何从透视矩阵中检测旋转角度?

How can I detect the rotation angle from a perspective matrix?

我写了这段代码，但是结果角度不超过40 ...

I wrote this code ,but the resulted angle doesn't exceed 40 ...

Mat mmat;
mmat.create(3,3,CV_32FC1);
mmat=getPerspectiveTransform(templPoints,imgPoints);
cout<< mmat<<endl<<endl;
float angle=acos(mmat.at<double>(0,0));
angle=(angle*180)/3.14;
cout<<"angle is"<<angle<<endl;

推荐答案

getPerspectiveTransform返回单应性矩阵，该矩阵可以按如下方式分解:

getPerspectiveTransform returns an homography matrix which can be decomposed like this:

[R11，R12，T1]

[R11,R12,T1]

[R21，R22，T2]

[R21,R22,T2]

[P，P，1]

R代表旋转矩阵，T代表平移，P代表透视变形.

R represents a rotation matrix, T represents a translation, and P represents a perspective warp.

有关旋转矩阵代表的更多信息:

More info on what rotation matrix represents:

http://en.wikipedia.org/wiki/Rotation_matrix

http://mathworld.wolfram.com/RotationMatrix.html

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