JS:如何更改函数中的变量(IIFE) [英] JS: How to change variable in function (IIFE)

问题描述

如何使用IIFE.n()更改s变量，因为现在它不起作用.我执行IIFE.n()之后，IIFE.s仍返回字符串"

How to change the s variable using IIFE.n() because now it doesn't work. After I execute IIFE.n() IIFE.s still returns "string"

我已经尝试过了，但是我宁愿使用let/const，也不希望将此变量传递给全局范围，我想将其保留在模块中.

I've tried with this but I rather use let/const and don't want to pass this variable to global scope I want to keep it in module.

const iife = (() => {
    let s = "string";
    const n = () => {
        s = 1e3;
    };
    return {
        s: s,
        n: n
    };
})()

当前，当我执行iife.n()时，它不会更改s变量(当我在s = 1e3之前添加return时，它返回1000，但iife.s仍返回字符串")

Currently when I do iife.n() it doesn't change the s variable (when I added return before s = 1e3 it returns 1000 but iife.s still returns "string")

推荐答案

它确实会更改 s ，但是您没有任何方法来获取更新后的值，因此看不到它正在改变.尝试此操作，您将看到更新的 s :

It does change s, but you don't have any way to get the updated value, so you can't see that it's changing. Try this and you'll see the updated s:

const iife = (() => {
    let s = "string";
    const n = () => {
        s = 1e3;
    };
    const gets = () => s;
    return {
        s: s,
        n: n,
        gets: gets
    };
})();

iife.n();
console.log(iife.gets());

iife.s 与 s 变量不同.该变量仅用于初始化属性，但并未永久链接.

iife.s is not the same as the s variable. The variable was just used to initialize the property, but they're not linked permanently.

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