用递增的计数器值替换子字符串 [英] Replace substrings with an incremented counter value

问题描述

基本上我正在寻找的是该线程的PHP版本:在每次出现字符串时查找，替换和递增

Basically what I'm looking for is the PHP version of this thread: Find, replace, and increment at each occurence of string

我想在rach行的开头将> 之后的关键字替换为递增计数器.

I would like to replace the keyword following > at the start of rach line with an incrementing counter.

如果我输入的是:

>num, blah, blah, blah

ATCGACTGAATCGA

>num, blah, blah, blah

ATCGATCGATCGATCG

>num, blah, blah, blah

ATCGATCGATCGATCG

我希望成为...

>0, blah, blah, blah

ATCGACTGAATCGA

>1, blah, blah, blah

ATCGATCGATCGATCG

>2, blah, blah, blah

ATCGATCGATCGATCG

推荐答案

$str = 'a hello a some a';
$i = 0;

while (strpos($str, 'a') !== false)
{
    $str = preg_replace('/a/', $i++, $str, 1);
}

echo $str;

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