颤抖:从其兄弟中获取窗口小部件的屏幕截图 [英] flutter: taking screenshots of a widget from its sibling

问题描述

我有一个视图，有两个孩子Widget A和Widget B并排站立.窗口小部件B有一个按钮，可触发窗口小部件A上的屏幕截图，

I have a view that has two children Widget A and Widget B, standing side by side. Widget B has a button that triggers a screenshot on Widget A,

，但指的是诸如这个，似乎屏幕捕获的实现必须保留在小部件A中.因此，小部件B中的按钮回调需要与小部件A对话.由于这两个都是有状态小部件，因此我发现B很难调用A在其状态内的功能.

but referring to questions such as this one, it seems that the implementation of screen capture must stay within Widget A. So the button callback in Widget B needs to talk to Widget A. Since both are stateful widgets, I find it difficult for B to call A's function inside its state.

各种提供程序和herintedWidget机制似乎可以很好地处理父级到子级状态传播，但是我不清楚如何处理同级.

The various provider and inheritedWidget mechanisms seem to handle parent-to-child state propagation nicely but it's unclear to me how to handle siblings.

有什么想法吗?

推荐答案

按照@pskink的提示回答此问题:

To answer this question as per @pskink 's tip:

只需将 GlobalKey 用作全局可访问变量，例如Widget A的静态成员，那么我们就可以在树中的任何地方引用A的上下文.

Just use GlobalKey as a globally accessible variable such as a static member of Widget A, then we could refer to A's context anywhere in the tree.

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