选择所有大于某个值的列 [英] Select all columns greater than some value
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问题描述
我是mysql的新手,我具有这样的结构
I am new to mysql and I have structure like this
timestamp | Name | Total | Student1 | Student2 | Student3
20150911 | X | 100 | 76 | 10 | NA
20151111 | Y | 70 | NA | 0 | 23
现在我要使用mysql查询选择给定的'时间戳'在哪里
Now I want to select with mysql query where at given 'timestamp'
- 所有非零学生列
- 所有不适用的学生专栏
- 所有学生列为零
预期结果
- 如果我输入非零"查询,则应将列名称命名为时间戳20150911的"Student1,Student2"
- 如果我输入零"查询,则应将时间戳20150911的列名称指定为().
- 如果我输入"NA"查询,则应为时间戳20150911将该列的名称指定为"Student3"
我已经尝试搜索这种混合选择,但是到目前为止,我还没有成功.大多数答案都集中在行选择而不是列上.
I have tried searching for such mixed selection but so far I am not successful. Most of answers are concentrating on row selection rather columns.
推荐答案
您的数据结构未规范化.但是,如果您想走这条路,请使用:
Your data structure is not normalized. But if you want to go this path use:
select sub.student
FROM (
select t.timestamp,
t.Name,
t.Total,
c.col AS student,
case c.col
when 'Student1' then Student1
when 'Student2' then Student2
when 'Student3' then Student3
-- ...
end as d
from mytable t
cross join
(
select 'Student1' as col
union all select 'Student2'
union all select 'Student3'
-- ...
) c
) AS sub
WHERE sub.timestamp = '20150911'
AND sub.d > 0;
-- sub.d = 'NA'
-- sub.d = 0
输出:
╔══════════╗
║ student ║
╠══════════╣
║ Student1 ║
║ Student2 ║
╚══════════╝
如果要用逗号分隔结果,请使用:
If you want comma separated result use:
select GROUP_CONCAT(sub.student ORDER BY sub.student) AS result
输出:
╔═══════════════════╗
║ result ║
╠═══════════════════╣
║ Student1,Student2 ║
╚═══════════════════╝
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