选择所有包含某个属性的 xml 节点 [英] select all xml nodes which contain a certain attribute

问题描述

我必须选择包含具有特定名称的属性的所有节点.

I have to select all nodes which contain an attribute with a certain name.

这是我目前的方法，不可行.

This is my current, not working approach.

public List<string> RetrieveValuesForAttribute(string attributeName)
{
    var list = new List<string>();

    string xpath = "//*[@Name='" + attributeName + "']";
    XmlNodeList xmlNodeList = document.SelectNodes(xpath);

    foreach (XmlNode xmlNode in xmlNodeList)
    {
        list.Add(xmlNode.Attributes[attributeName].InnerText);
    }

    return list;
} 

我尝试选择包含方法参数 attributeName 中给定名称的属性的所有节点，并将值添加到变量 list.

I try to select all nodes which contain the attribute with the name given in the method parameter attributeName and add the value the variable list.

示例:

这个方法调用:

List<string> result = RetrieveValuesForAttribute("itemSelectedHandler");

应该返回一个包含字符串OnSelectedRelatedContactChanged"的列表

Should return an list which contains the string "OnSelectedRelatedContactChanged"

这是xml文件:

<GroupBoxWrapper id="gbRelatedContacts" text="Related Contacts">
  <TabIndex>0</TabIndex>
  <TabStop>false</TabStop>
  <PanelWrapper id="pnlRelatedContactsView" width="1350">
    <TabIndex>0</TabIndex>
    <TabStop>false</TabStop>
    <ListViewWrapper id="lvRelatedContacts" itemSelectedHandler="OnSelectedRelatedContactChanged" itemDoubleClickHandler="OnRelatedContactDoubleClick">
      <TabIndex>0</TabIndex>
      <TabStop>true</TabStop>
      <ListViewColumns>
        <Column title="Name" mapNode="Contact\Name" />
        <Column title="Lastname" mapNode="Contact\Lastname" />
      </ListViewColumns>
    </ListViewWrapper>
  </PanelWrapper>
</GroupBoxWrapper>

其他问题:用 LINQ 解决这个问题会更好吗?

Further questions: Would it be better to solve this with LINQ?

解决方案 1:谢谢你，ywm

public List<string> RetrieveValuesForAttribute(string attributeName)
{
    var list = new List<string>();

    string xpath = @"//*[@" + attributeName + "]";
    XmlNodeList xmlNodeList = document.SelectNodes(xpath);

    foreach (XmlNode xmlNode in xmlNodeList)
    {
        list.Add(xmlNode.Attributes[attributeName].InnerText);
    }

    return list;
}

解决方案 2:谢谢你，乔恩·斯基特

public List<string> RetrieveValuesForAttribute(string attributeName)
{
    //document is an XDocument
    return document.Descendants()
                   .Attributes(attributeName)
                   .Select(x => x.Value)
                   .ToList();
}

LINQ to XML 解决方案在我看来要优雅得多.

The LINQ to XML Solution looks far more elegant to me.

推荐答案

如果您可以为此使用 LINQ to XML，那将是微不足道的:

If you could use LINQ to XML for this, it would be utterly trivial:

// Note that there's an implicit conversion from string to XName,
// but this would let you specify a namespaced version if you want.
public List<string> RetrieveValuesForAttribute(XName attributeName)
{
    // Assume document is an XDocument
    return document.Descendants()
                   .Attributes(attributeName)
                   .Select(x => x.Value)
                   .ToList();
} 

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