XPath 选择所有父节点不包含特定属性和值的节点 [英] XPath Select Nodes where all parent nodes do not contain specific attribute and value

问题描述

我有以下 XML 结构:

I have the following XML structure:

<root>
  <Level1 IsEnabled="0"> <!-- Disabled -->
    <Level2 IsEnabled="1">
      <Level3 IsEnabled="1">
        <Level4 IsEnabled="1">
          <Child /> <!-- Don't include this one -->
        </Level4>
      </Level3>
    </Level2>
  </Level1>
  <Level1 IsEnabled="1">
    <Level2 IsEnabled="1">
      <Level3 IsEnabled="0"> <!-- Disabled -->
        <Level4 IsEnabled="1">
          <Child /> <!-- Don't include this one -->
        </Level4>
      </Level3>
    </Level2>
  </Level1>
  <Level1 IsEnabled="1">
    <Level2 IsEnabled="1">
      <Level3 IsEnabled="1">
        <Level4 IsEnabled="1">
          <Child /><!-- Include this one -->
        </Level4>
      </Level3>
    </Level2>
   </Level1>
</root>

我想选择其任何祖先不包含 IsEnabled="0" 的所有子节点.所以对于上面的 XML，我只想选择最后一个子节点.此外，如果祖先节点不包含 IsEnabled 属性，则仍应包含子节点.

I want to select all child nodes where any of its ancestors do not contain IsEnabled="0". So for the XML above I only want to select the last child node. In addition, if a ancestor node doesn't contain a IsEnabled attribute, then the child should still be included.

推荐答案

问:我想选择其任何祖先不包含 IsEnabled="0" 的所有子节点试试这个:

Q: I want to select all child nodes where any of its ancestors do not contain IsEnabled="0" Try this:

//Child[not(ancestor::*[@IsEnabled='0'])]

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