前一个工作日在Python [英] Previous weekday in Python

问题描述

在Python中，给定日期，我如何找到前一个工作日?(工作日是星期一至星期五.我不在乎假期)

In Python, given a date, how do I find the preceding weekday? (Weekdays are Mon to Fri. I don't care about holidays)

推荐答案

从给定日期中减去一天，然后检查该日期是否为工作日.如果没有，减去另一个，直到您有一个工作日:

Simply subtract a day from the given date, then check if the date is a weekday. If not, subtract another, until you do have a weekday:

from datetime import date, timedelta
def prev_weekday(adate):
    adate -= timedelta(days=1)
    while adate.weekday() > 4: # Mon-Fri are 0-4
        adate -= timedelta(days=1)
    return adate

演示:

>>> prev_weekday(date.today())
datetime.date(2012, 8, 20)
>>> prev_weekday(date(2012, 8, 20))
datetime.date(2012, 8, 17)

或者，使用偏移表；无需对此进行映射，元组就可以了:

Alternatively, use an offset table; no need to make this a mapping, a tuple will do just fine:

_offsets = (3, 1, 1, 1, 1, 1, 2)
def prev_weekday(adate):
    return adate - timedelta(days=_offsets[adate.weekday()])

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