Python的工作日 [英] Business days in Python

问题描述

我需要从当前日期减去工作日。

I need to subtract business days from the current date.

我目前有一些需要永远在最近一个工作日运行的代码。所以如果我们星期一到星期五可能是今天，但如果是星期六或星期天，那么我需要把它设置回周末的周五。我目前有一些很好的笨重代码来执行此操作：

I currently have some code which needs always to be running on the most recent business day. So that may be today if we're Monday thru Friday, but if it's Saturday or Sunday then I need to set it back to the Friday before the weekend. I currently have some pretty clunky code to do this:

 lastBusDay = datetime.datetime.today()
 if datetime.date.weekday(lastBusDay) == 5:      #if it's Saturday
     lastBusDay = lastBusDay - datetime.timedelta(days = 1) #then make it Friday
 elif datetime.date.weekday(lastBusDay) == 6:      #if it's Sunday
     lastBusDay = lastBusDay - datetime.timedelta(days = 2); #then make it Friday

有更好的方法吗？

我可以告诉timedelta在平日而不是日历日工作吗？

Can I tell timedelta to work in weekdays rather than calendar days for example?

推荐答案

使用大熊猫

import pandas as pd
# BDay is business day, not birthday...
from pandas.tseries.offsets import BDay

# pd.datetime is an alias for datetime.datetime
today = pd.datetime.today()
print today - BDay(4)

由于今天是9月26日星期四，这将给你一个输出：

Since today is Thursday, Sept 26, that will give you an output of:

datetime.datetime(2013, 9, 20, 14, 8, 4, 89761)

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