MySQL Group从季度到期间 [英] MySQL Group from quarters to periods

问题描述

我有一个这样的表:

Person smallint(5)  act_time datetime
1   2020-05-29 07:00:00
1   2020-05-29 07:15:00
1   2020-05-29 07:30:00
2   2020-05-29 07:15:00
2   2020-05-29 07:30:00
1   2020-05-29 10:30:00
1   2020-05-29 10:45:00

上表是一个示例，其中有2个不同的人，他们工作的每个季度都有一行...

The table above is an example with 2 different persons and there is a row for each quarter they are at work...

在MySQL中将表转换"到另一个表的最佳方法是什么，在该表中有一个列"person"，一个列"start"和一个"stop".

What is the best way in MySQL to "convert" this table to another table where there is a column for "person", a column for "start" and one for "stop".

结果是这样的:

Person  Start   Stop
1   2020-05-29 07:00:00   2020-05-29 07:45:00
2   2020-05-29 07:15:00   2020-05-29 07:45:00
1   2020-05-29 10:30:00   2020-05-29 11:00:00

我尝试过左连接到相同的原始表，但是没有用...

I have tried with a left join to the same original table but it didn't work...

感谢您的答复.我现在已经在上表中进行了尝试-不幸的是它没有给出结果...我的sql字符串是:

Thanks for your reply. I have now tried it with the table above - and it unfortunately doesn't give that result... My sql string is:

select person,min(act_time) start_date,max(act_time) end_date from (select t.*,row_number() over(order by act_time) rn1,row_number() over(partition by person order by act_time) rn2 from test t) t group by person, rn1 - rn2 order by min(act_time)

But the result it generates is:
1 29-05-2020 07:00:00 29-05-2020 07:15:00
2 29-05-2020 07:15:00 29-05-2020 07:15:00
1 29-05-2020 07:30:00 29-05-2020 07:30:00
2 29-05-2020 07:30:00 29-05-2020 07:30:00
1 29-05-2020 10:30:00 29-05-2020 10:45:00

应该类似于3行的结果.因此，当同一个人的行之间的间隔超过15分钟时，应该创建一个新行.

It should be like the result with 3 rows. So when there is a gap in more than 15 minutes between to rows with the same person it should create a new row.

推荐答案

这是一个孤岛问题.我不确定为什么GMB的解决方案不起作用，但这应该:

This is a gaps-and-islands problem. I'm not sure why GMB's solution doesn't work, but this should:

select person, min(act_date) as start_date,
       max(act_date) + interval 15 minute as end_date
from (select t.*,
             sum(case when prev_act_date >= act_date - interval 15 minute then 0 else 1 end) over
                 (partition by person order by act_date) as grp
      from (select t.*,
                   lag(act_date) over (partition by person order by act_date) as prev_act_date
            from t
           ) t
     ) t
group by person, grp
order by min(act_date)

这篇关于MySQL Group从季度到期间的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！