按日期字段YYYY-MM-DD hh-mm-ss.sss对JSONArray字符串排序 [英] Sorting a JSONArray string by its date field YYYY-MM-DD hh-mm-ss.sss

问题描述

我有一个格式化为这样的字符串的JSONArray:

I have a JSONArray formatted as a string like this:

[{"2016-11-09 19:01:59.649":"[e-mail]::example message"},
{"2016-11-09 19:01:05.542":"[e-mail]::another example"},
{"2016-11-09 19:02:01.394":"[e-mail]::another one"}]

有没有一种有效的方法可以按时间顺序对所有JSON对象进行排序?

Is there some efficient way to sort all the JSON objects in chronological order?

推荐答案

假设您在 JSONObject 实例中只有一个条目，则可以:

Assuming that you have only one entry in your JSONObject instances, you could:

1. 从 JSONArray
中提取 JSONObject 实例
2. 通过比较 JSONObject s的第一个键
对 JSONObject 的数组进行排序
3. 然后创建一个新的 JSONArray 或在旧的 JSONArray 中重新设置值.

1. Extract the JSONObject instances from the JSONArray,
2. Sort the array of JSONObject by comparing the first key of the JSONObjects,
3. Then create a new JSONArray or re-set values in the old JSONArray.

类似这样的东西:

// Build the source JSONArray
JSONArray array = new JSONArray();
array.put(
    new JSONObject("{\"2016-11-09 19:01:59.649\":\"[e-mail]::example message\"}")
);
array.put(
    new JSONObject("{\"2016-11-09 19:01:05.542\":\"[e-mail]::another example\"}")
);
array.put(
    new JSONObject("{\"2016-11-09 19:02:01.394\":\"[e-mail]::another one\"}")
);

// Extract the JSONObjects
JSONObject[] objects = new JSONObject[array.length()];
for (int i = 0; i < objects.length; i++) {
    objects[i] = array.getJSONObject(i);
}
// Sort the array of JSONObjects
Arrays.sort(
    objects,
    (JSONObject o1, JSONObject o2) ->
        ((String)o1.keys().next()).compareTo((String)o2.keys().next())
);
// Build a new JSONArray from the sorted array
JSONArray array2 = new JSONArray();
for (JSONObject o : objects) {
    array2.put(o);
}
System.out.println(array2);

输出:

[{"2016-11-09 19:01:05.542":"[e-mail]::another example"},{"2016-11-09 19:01:59.649":"[e-mail]::example message"},{"2016-11-09 19:02:01.394":"[e-mail]::another one"}]

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