解析yyyy-MM-dd HH:mm:ss日期时间字符串? [英] Parsing yyyy-MM-dd HH:mm:ss date time string?
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问题描述
我有一个来自mysql的日期时间。我需要提取每个部分:
int year;
int month;
int day;
int hour;
int min;
int sec;
例如:
code> 2014-06-10 20:05:57
运行它通过stringstream为每个组件? (无需boost或c ++ 11解决方案。)
感谢
解决方案<
sscanf()
可能是最直接的选择。
这里是一个例子:
int year;
int month;
int day;
int hour;
int min;
int sec;
const char * str =2014-06-10 20:05:57;
if(sscanf(str,%d-%d-%d%d:%d:%d,& year,& month,& day,& hour,& ; min,& sec)== 6)
{
// sscanf()返回扫描的元素数量,因此6表示包含所有6个元素的字符串。
//否则可能是格式错误。
}
另一个不错的解决方案是使用 C ++ 11 regex ,这将使字符串的解析更加强大。
I have a date time that comes from mysql. I need to extract each part:
int year;
int month;
int day;
int hour;
int min;
int sec;
example:
2014-06-10 20:05:57
Is there a simpler way than running it through stringstream for each component? (no boost or c++11 solutions please).
Thanks
解决方案
sscanf()
is probably the most straightforward option. It is a C library function, so purists might disapprove it.
Here is an example:
int year;
int month;
int day;
int hour;
int min;
int sec;
const char * str = "2014-06-10 20:05:57";
if (sscanf(str, "%d-%d-%d %d:%d:%d", &year, &month, &day, &hour, &min, &sec) == 6)
{
// sscanf() returns the number of elements scanned, so 6 means the string had all 6 elements.
// Else it was probably malformed.
}
Another nice solution would also be to use a C++11 regex which would make for a more robust parsing of the string.
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