date()格式，d-m-Y和d/m/Y之间的差异 [英] date() format, differences between d-m-Y and d/m/Y

问题描述

这是我的第一篇文章，对不起，如果我做错了.好吧，我得到了这段代码

this is my first post so sorry if i do something wrong. Well I got this code

$min=date('d-m-Y');

$max=date ('31-12-2015');


function rand_date($min, $max) {


    $min_epoch = strtotime($min);
    $max_epoch = strtotime($max);

    $rand_epoch = rand($min_epoch, $max_epoch);

    return date('d-m-Y H:i:s', $rand_epoch);
}

echo rand_date($min, $max);//return 04-12-2015 07:48:22`

它可以工作，但是当我将其与我需要的格式(d/m/Y)一起使用时，问题就来了

It works, but the problem comes when I use this with the format than i need (d/m/Y)

$min=date('d/m/Y');

$max=date ('31/12/2015');


function rand_date($min, $max) {


    $min_epoch = strtotime($min);
    $max_epoch = strtotime($max);

    $rand_epoch = rand($min_epoch, $max_epoch);

    return date('d/m/Y H:i:s', $rand_epoch);
}

echo rand_date($min, $max);// Always shows 01/01/1970 01:00:00`.

我需要使用这种格式，所以如果有人回答我的问题，我将不胜感激.

I need works with this format, so I will be grateful if somebody answer my question.

推荐答案

PHP日期/时间函数/方法的 31/12/2015 的默认解释为 m/d/Y(使用正斜杠)和 dmY 或 Ymd (如果使用破折号)，如果您

The default interpretation of 31/12/2015 for PHP date/time functions/methods is m/d/Y when using forward-slashes, and d-m-Y or Y-m-d when using dashes, if you check the manual. Which is why something like date('31/12/2015') returns false since there is no 31st month in a year.

使用 DateTime :: createFromFormat 来指定您自己的变体你必须.

Use DateTime::createFromFormat instead to specify your own variations if you must.

$min = new DateTime;

$max = DateTime::createFromFormat('d/m/Y', '31/12/2015');


function rand_date(DateTime $min, DateTime $max) {
    $min_epoch = $min->getTimeStamp();
    $max_epoch = $max->getTimeStamp();

    $rand_epoch = rand($min_epoch, $max_epoch);

    return (new DateTime("@$rand_epoch"))->format('d/m/Y H:i:s');
}

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