Python中的词频程序 [英] word frequency program in python

问题描述

说我有一个单词列表，称为单词，即单词= ["hello"，"test"，"string"，"people"，"hello"，"hello"]，我想创建一个字典以获取单词频率.

Say I have a list of words called words i.e. words = ["hello", "test", "string", "people", "hello", "hello"] and I want to create a dictionary in order to get word frequency.

比方说字典叫做计数"

Let's say the dictionary is called 'counts'

counts = {}
for w in words:
    counts[w] = counts.get(w,0) + 1

我唯一不了解的部分是counts.get(w.0).这本书说，通常您会使用counts [w] = counts [w] + 1，但是第一次遇到新单词时，它不会出现在counts中，因此会返回运行时错误.一切都很好，但是counts.get(w，0)到底是做什么的?具体来说，(w，0)表示法是什么?

The only part of this I don't really understand is the counts.get(w.0). The book says, normally you would use counts[w] = counts[w] + 1 but the first time you encounter a new word, it won't be in counts and so it would return a runtime error. That all fine and dandy but what exactly does counts.get(w,0) do? Specifically, what's the (w,0) notation all about?

推荐答案

如果您有字典，则 get()是一种方法，其中 w 是持有变量的变量.您要查找的单词，默认值为 0 .如果字典中不存在 w ，则 get 返回 0 .

If you have a dictionary, get() is a method where w is a variable holding the word you're looking up and 0 is the default value. If w is not present in the dictionary, get returns 0.

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