使用python删除嵌套字典中的键及其值 [英] Remove key and its value in nested dictionary using python

问题描述

寻找一种通用解决方案，在该解决方案中，我可以从dict中删除特定键及其值.例如，如果 dict 包含以下嵌套的键值对:

Looking for a generic solution where I can remove the specific key and its value from dict. For example, if dict contains the following nested key-value pair:

data={

  "set": {
  "type": "object", #<-- should remove this key:value pair
  "properties": {
    "action": {
      "type": "string",  #<-- should NOT remove this key:value pair
      "description": "My settings"
    },
    "settings": {
      "type": "object", #<-- should remove this key:value pair
      "description": "for settings",
      "properties": {
        "temperature": {
          "type": "object", #<-- should remove this key:value pair
          "description": "temperature in degree C",
          "properties": {
            "heater": {
              "type": "object", #<-- should remove this key:value pair
              "properties": {
                "setpoint": {
                  "type": "number"
                },
              },
              "additionalProperties": false
            },

          },
          "additionalProperties": false
        },

      },
      "additionalProperties": false
    }
  },
  "additionalProperties": false
}
}

我希望在整个key:value对出现时没有"type":"object" 的输出 dict .预期的输出应生成没有"type":"object"

I want an output dict without "type":"object" across the occurrence of this key:value pair. The expected output should produce the result without "type":"object"

推荐答案

您可以编写一个递归函数:

You can write a recursive function:

def remove_a_key(d, remove_key):
    if isinstance(d, dict):
        for key in list(d.keys()):
            if key == remove_key:
                del d[key]
            else:
                remove_a_key(d[key], remove_key)

并将其称为:

remove_a_key(data, 'type')

这将递归地删除'type'键，并且无论它有多深，它都会从每个嵌套字典中删除.

This recursively removes 'type' key and it's value from each nested dictionary no matter how deep it is.

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