Python3，订购一个复杂的字典 [英] Python3, ordering a complex dict

问题描述

我有一个复杂的Python字典，该字典存储以下值:MAC地址，RSSI和时间戳:

I've got a complex Python dictionary that stores the following values: MAC ADDRESS, RSSI and TIMESTAMP:

beacons_detected = {
    '55:c1:9a:41:4c:b9': ['-78', '1493580469'],
    '9c:20:7b:e0:6c:41': ['-74', '1493622425'],
    '5e:30:e7:12:97:64': ['-79', '1493587968']
}

我想根据时间戳订购该列表...有关如何实现此目标的任何想法?

I would like to order that list based on timestamp... any idea on how to achieve that?

推荐答案

将字典从最小到最大排序:

sort the dictionary from smallest to largest:

>>> sorted(beacons_detected.items(), key=lambda x: x[1][1])
[('55:c1:9a:41:4c:b9', ['-78', '1493580469']), ('5e:30:e7:12:97:64', ['-79', '1493587968']), ('9c:20:7b:e0:6c:41', ['-74', '1493622425'])]

将字典从大到小排序:

>>> sorted(beacons_detected.items(), key=lambda x: x[1][1], reverse=True)
[('9c:20:7b:e0:6c:41', ['-74', '1493622425']), ('5e:30:e7:12:97:64', ['-79', '1493587968']), ('55:c1:9a:41:4c:b9', ['-78', '1493580469'])]

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