在一行中打印一个 int 列表 python3 [英] Printing an int list in a single line python3

问题描述

我是 python 的新手，我正在尝试在一行中扫描由空格分隔的多个数字(假设以1 2 3"为例)，并将其添加到 int 列表中.我是通过使用做到的:

I'm new to python and I'm trying to scan multiple numbers separated by spaces (let's assume '1 2 3' as an example) in a single line and add it to a list of int. I did it by using:

#gets the string 
string = input('Input numbers: ') 
#converts the string into an array of int, excluding the whitespaces
array = [int(s) for s in string.split()] 

显然它有效，因为当我输入1 2 3"并执行 print(array) 时，输出是:

Apparently it works, since when I type in '1 2 3' and do a print(array) the output is:

[1, 2, 3]

但我想把它打印成一行，没有括号，数字之间有一个空格，就像这样:

But I want to print it in a single line without the brackets, and with a space in between the numbers, like this:

1 2 3

我尝试过:

for i in array:
    print(array[i], end=" ")

但我收到一个错误:

2 3 回溯(最近一次调用最后一次):

2 3 Traceback (most recent call last):

print(array[i], end="")

print(array[i], end=" ")

IndexError: 列表索引超出范围

IndexError: list index out of range

如何在一行中打印整数列表(假设我的前两行代码是正确的)，并且没有括号和逗号?

How can I print the list of ints (assuming my first two lines of code are right) in a single line, and without the brackets and commas?

推荐答案

你想说

for i in array:
    print(i, end=" ")

语法i in array 迭代列表的每个成员.因此，array[i] 试图访问 array[1]、array[2] 和 array[3]，但最后一个越界(array 的索引为 0、1 和 2).

The syntax i in array iterates over each member of the list. So, array[i] was trying to access array[1], array[2], and array[3], but the last of these is out of bounds (array has indices 0, 1, and 2).

你可以用print(" ".join(map(str,array)))获得同样的效果.

You can get the same effect with print(" ".join(map(str,array))).

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