使用其他字典过滤python字典 [英] Filtering a python dictionary using another dictionary

问题描述

我目前正在尝试寻找一种使用另一种字典过滤字典的更pythonic的方法.目前，我有以下代码:

I am currently trying to find a more pythonic way of filtering a dictionary using another dictionary. Currently I have the following code:

def filter_respondents(data_dict, tolerance):
    NaN_dict = diagnostic_tools.get_NaN_ratio(data_dict)
    final_dict = {}            
    for respondent in data_dict:
        if NaN_dict[respondent]<=tolerance:
            final_dict[respondent] = data_dict[respondent]    
return final_dict

代码可以完成我想要的工作，但是我正在寻找一种更好的方法.基本上我有2本字典.data_dict是具有键值对id:response的字典，而NaN_dict是键值对id:value的字典.如果值低于公差，我希望将data_dict中具有相同ID的键值对包含在final_dict中.

The code does what I want it to do but I'm looking for a better way of doing it. Basically I have 2 dictionaries. data_dict is a dictionary with the key-value pairs id:response and NaN_dict has the key-value pairs id:value. If value is below tolerance, I want the key-value pair with the same ID in data_dict to be included in final_dict.

我想出了类似的东西:

final_dict = {k:v for k,v in data_dict if NaN_dict[k]<=tolerance}  

我知道这是错的，但是我不确定如何继续.谢谢！

Which I know is wrong, but I'm not sure how to proceed. Thanks!

推荐答案

我认为您几乎是正确的.似乎唯一缺少的是调用 .items()以获取键值对:

I think you are almost right. Seems that the only thing missing is to call .items() for getting key-value pairs:

{k: v for k, v in data_dict.items() if NaN_dict[k] <= tolerance}

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