使用秋千将平铺图像绘制为一张2D平铺地图的大图像 [英] Draw Tile images to one large Image for 2d Tile Map with swing

问题描述

我正在尝试为2D Tile游戏绘制地图，我可以使用一些帮助.这是应该绘制地图的类.

I am trying to draw a map for a 2D Tile game and I could use some help. Here is the class that is supposed to draw the map.

`package view;
import java.awt.*;
import java.awt.image.BufferedImage;

import model.*;

import javax.swing.*;
public class DrawMap extends JPanel{
    private static  Map map = Map.getMap(); 
    private static Tile[][] field = map.getField();
    BufferedImage im = new BufferedImage(3000,3000,BufferedImage.TYPE_INT_RGB);

    public DrawMap() {
        init();


    }
    public void init(){
        Graphics g = im.getGraphics();
        for(int i = 0; i < 100; i++){
            for(int j = 0; j < 100; j++){
                field[i][j].drawTile(g);
            }
        }
    }
    public void paintComponent(Graphics g){
        super.paintComponent(g);
        g.drawImage(im,0,0,null);

    }

    public static void main(String[] args){
        JFrame frame = new JFrame("GameMap");
        DrawMap draw = new DrawMap();
        frame.add(draw);
        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        frame.pack();
        frame.setVisible(true);
    }

}
`

从本质上讲，这将创建一个新的图像，该图像将成为地图，然后我遍历2D数组并调用drawTile，该命令应该将图块Image绘制到我刚刚创建的地图Image上.这是drawTile的外观.我不应该认为img是一个私有的BufferedImage，在尝试在drawTile中将其设置之前，它不会设置任何内容.

Essentially this makes a new Image that is going to be the map, then I go through my 2D array and call drawTile which is supposed to draw that tiles Image to the map Image I just created. Here is what drawTile looks like. I should not that img is a private BufferedImage that is not set to anything until I try to set it here in drawTile.

    'public void drawTile(Graphics g){
    try{
        img = ImageIO.read(new File("src/model/tileTest.png"));
    }catch (IOException e){
        e.printStackTrace(System.out);
    }
    g.drawImage(img, this.getXChord(), this.getYChord(), null);




}'

读取图像文件时出现内存不足错误.如果我使drawMap类仅搜索前50个图块，则会得到一个图像，但这是一堆非常小的图块和1个大图块.我应该如何读取图像，以免出现内存不足错误.如果可能的话，我想使用缓冲的图像.我还想我在drawTile中调用g.drawImage时需要使用某种宽度和高度参数，但是我不确定从哪里开始.

I am getting an Out of memory error from reading the image file. If I make the drawMap class only search through the first 50 tiles I get an image but it is a bunch of really small tiles and 1 large image tile. How should I be reading in the image so I don't get the out of memory error. Id like to use buffered image if possible. Also Im thinking I will need to use some kind of width and height parameters when I call g.drawImage in drawTile but I am not sure where to begin with that.

感谢您的帮助

推荐答案

您正在为每个图块运行以下代码:

You're running this code for every tile:

public void drawTile(Graphics g){
    try {
        img = ImageIO.read(new File("src/model/tileTest.png"));
    } catch (IOException e) {
        e.printStackTrace(System.out);
    }
    g.drawImage(img, this.getXChord(), this.getYChord(), null);
}

这意味着您正在重新读取每个图块的图像 .对于您渲染的每个图块，每秒60次，您就遇到了硬盘驱动器并捕获了该图像.图片可能会缓存在内存中，因此内存不足.

That means you're rereading the image for every tile. For every tile you render, 60 times a second, you're running into your hard drive and grabbing that image. The images might be cached in memory, and thus it's running out of memory.

您肯定应该创建一张图像并多次使用.例如:

You definitely should be creating one image and using it multiple times. For example:

static Image img = null;

public Tile() {
    if (img == null) {
        try {
            img = ImageIO.read(new File("src/model/tileTest.png"));
        } catch (IOException e) {
            e.printStackTrace(System.out);
        }
    }
}

public void drawTile(Graphics g) {
    g.drawImage(img, this.getXChord(), this.getYChord(), null);
}

随着您获得越来越多的图块，您可能需要一个更全面的解决方案.但是现在这应该可以解决您的问题.

As you get more and more tiles, you may want a more robut solution. But for now this should solve your problem.

(顺便说一句， e.printStackTrace(System.out)与 e.printStackTrace();相同)

(By the way, e.printStackTrace(System.out) is identical to e.printStackTrace() ;)

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