列表聚合的python字典 [英] python dictionary of list of list aggregate

问题描述

我有可用的时间序列字典，我需要计算每个键的所有值，最有效的方法是什么?

I have timeseries dictionary available, I need to count all the values of each keys, what's the most efficient way to do this?

DATA = {u'604':[[1361836800，{u'14885549':52，u'91478624':127，u'25581439':12，u'532617990':4}]，[1361833200，{u'14885549':38，u'91478624':204，u'25581439':14，u'40302362':5，u'532617990':2}]]}

DATA = {u'604': [[1361836800, {u'14885549': 52, u'91478624': 127, u'25581439': 12, u'532617990': 4}], [1361833200, {u'14885549': 38, u'91478624': 204, u'25581439': 14, u'40302362': 5, u'532617990': 2}]]}

我在这里尝试这样做(虽然确实很愚蠢，但是可行):

My attempt to do this is here (which is surely idiotic but works):

total = 0
for i in DATA:
    for j in DATA[i]:
        for k in j[1]:
            total += j[1][k]

请帮助?

推荐答案

将 sum()与生成器配合使用:

total = sum(sum(inner[1].values()) for outer in DATA.values() for inner in outer)

这在行为上等同于以下for循环:

This is equivalent in behavior to the following for loop:

total = 0
for outer in DATA.values():
    for inner in outer:
        total += sum(inner[1].values())

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