字典搜索的 Python 列表 [英] Python list of dictionaries search

问题描述

假设我有这个:

<预><代码>[{姓名":汤姆"，年龄":10}，{姓名":马克"，年龄":5}，{姓名":帕姆"，年龄":7}]

并通过搜索Pam"作为名称，我想检索相关字典:{name: "Pam", age: 7}

如何实现?

解决方案

您可以使用 生成器表达式:

<预><代码>>>>字典 = [... { "name": "Tom", "age": 10 },... { "name": "Mark", "age": 5 },... { "name": "Pam", "age": 7 },... {姓名":迪克"，年龄":12 }...]>>>next(如果 item["name"] == "Pam"，则为 dicts 中的 item 的 item){'年龄':7，'姓名':'帕姆'}

如果您需要处理不在那里的项目，那么您可以执行 user Matt 在他的评论中建议 并使用稍微不同的 API 提供默认值:

next((item for item in dicts if item["name"] == "Pam"), None)

并且要查找项目的索引，而不是项目本身，您可以enumerate() 列表:

next((i for i, item in enumerate(dicts) if item["name"] == "Pam"), None)

Assume I have this:

[
  {"name": "Tom", "age": 10},
  {"name": "Mark", "age": 5},
  {"name": "Pam", "age": 7}
]

and by searching "Pam" as name, I want to retrieve the related dictionary: {name: "Pam", age: 7}

How to achieve this ?

解决方案

You can use a generator expression:

>>> dicts = [
...     { "name": "Tom", "age": 10 },
...     { "name": "Mark", "age": 5 },
...     { "name": "Pam", "age": 7 },
...     { "name": "Dick", "age": 12 }
... ]

>>> next(item for item in dicts if item["name"] == "Pam")
{'age': 7, 'name': 'Pam'}

If you need to handle the item not being there, then you can do what user Matt suggested in his comment and provide a default using a slightly different API:

next((item for item in dicts if item["name"] == "Pam"), None)

And to find the index of the item, rather than the item itself, you can enumerate() the list:

next((i for i, item in enumerate(dicts) if item["name"] == "Pam"), None)

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