将元素追加到列表字典中的最小列表 [英] Append element to smallest list in dictionary of lists

问题描述

我有一个列表字典，我想为其添加值到特定列表...

I have a dictionary of lists for which I want to add a value to a particular list...

d = {'a': [4, 2], 'b': [3, 4], 'c': [4, 3], 'd': [4, 3], 'e': [4], 'f': [4], 'g': [4]}

我想将2加到长度最小的列表中.

I want to add the number 2 to the just one of the lists with the smallest length.

def gsl(x):
    return [k for k in x.keys() if len(x.get(k))==min([len(n) for n in x.values()])]

致电后

>>> gsl(d)
['e', 'g', 'f']

因此，在这种情况下，我想将数字2附加到字典中的列表'e'中，使其成为 [4,2] (顺序无关紧要.

So in this case, I want to append the number 2 to the list 'e' in the dictionary making it [4,2] (order doesnt matter.

结果应为

>>> d['e']
[4,2]

我尝试过

for i in d:
    if gsl(d)[0] == i: #gets the first key with the smallest value 
        d[i].append(2) # if equal, adds 2 to the dictionary value that matches

除了在每个'e'，'g'，'f'中添加 2 .

Except that adds 2 to each 'e', 'g', 'f'.

提前谢谢！

推荐答案

>>> d = {'a': [4, 2], 'b': [3, 4], 'c': [4, 3], 'd': [4, 3], 'e': [4], 'f': [4], 'g': [4]}
>>> smallest = min(d, key=lambda k: len(d[k]))
>>> d[smallest].append(2)
>>> d
{'a': [4, 2], 'c': [4, 3], 'b': [3, 4], 'e': [4, 2], 'd': [4, 3], 'g': [4], 'f': [4]}

这篇关于将元素追加到列表字典中的最小列表的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！