将列表追加到R中的列表列表 [英] Appending a list to a list of lists in R

问题描述

我在将数据附加到已经采用列表格式的列表时遇到问题.我有一个程序，它将在模拟循环中导出结果对象.数据本身存储为矩阵列表.我的想法是将这些列表存储在一个列表中，然后将该列表列表另存为R对象以供以后分析，但是我在正确实现此功能方面存在一些问题.我将展示我对小型抽象示例所做的工作，仅使用值而不是模拟中的矩阵数据即可完成

I'm having issues appending data to a list which is already in a list format. I have a program which will export results objects during a simulation loop. The data itself is stored as a list of matrices. My idea is to store those lists in a list, and then save this list of lists as an R object for later analysis, however I'm having some issues achieving this correctly. I'll show what I've done with small abstract example just using values instead of the matrix data from my simulation:

说我已经运行了3次仿真循环. 在迭代过程中，需要将结果列表收集到我将另存为R对象的一个​​列表列表中:

Say I've run the simulation loop for 3 times. During the iterations, the results lists need to be collected into the one list of lists that I will save as an R object:

包含其他列表并保存的列表: outlist1 <- list()

List to contain the other lists and be saved: outlist1 <- list()

第一次迭代: resultsa <- list(1,2,3,4,5)

outlist <- append(outlist1,resultsa)

第二个迭代: resultsb <- list(6,7,8,9,10)

outlist <- append(outlist1,b)

第三次迭代: resultsc <- list(11,12,13,14,15)

outlist <- list(outlist2,c)

但是，此解决方案不适用于以这种方式生成包含列表的列表，期望的结果是:

However, this solution does not work with growing a list containing lists this way, the desired result is:

>outlist
[[1]]
[[1]][[1]]
[1] 1

[[1]][[2]]
[1] 2

[[1]][[3]]
[1] 3

[[1]][[4]]
[1] 4

[[1]][[5]]
[1] 5


[[2]]
[[2]][[1]]
[1] 6

[[2]][[2]]
[1] 7

[[2]][[3]]
[1] 8

[[2]][[4]]
[1] 9

[[2]][[5]]
[1] 10


[[3]]
[[3]][[1]]
[1] 11

[[3]][[2]]
[1] 12

[[3]][[3]]
[1] 13

[[3]][[4]]
[1] 14

[[3]][[5]]
[1] 15

但是，我得到的却是:

> outlist3
[[1]]
[[1]][[1]]
[[1]][[1]][[1]]
[1] 1

[[1]][[1]][[2]]
[1] 2

[[1]][[1]][[3]]
[1] 3

[[1]][[1]][[4]]
[1] 4

[[1]][[1]][[5]]
[1] 5


[[1]][[2]]
[[1]][[2]][[1]]
[1] 6

[[1]][[2]][[2]]
[1] 7

[[1]][[2]][[3]]
[1] 8

[[1]][[2]][[4]]
[1] 9

[[1]][[2]][[5]]
[1] 10

我如何增加列表，以使格式化后的列表像期望的结果一样?如果要对这些列表进行进一步分析，我需要能够轻松访问这些元素.

How do I grow a list, such that the resulting list formatted is like the desired result? If I do further analysis on these list I need to be able to easily access the elements.

推荐答案

是您想要的吗?

# Initial list:
myList <- list()

# Now the new experiments
for(i in 1:3){
  myList[[length(myList)+1]] <- list(sample(1:3))
}

myList

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