AUTH_USER_MODEL不接受子申请 [英] AUTH_USER_MODEL does not accept sub application

查看:55
本文介绍了AUTH_USER_MODEL不接受子申请的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

在使用 Django 1.7.1 Python 3.4 时,我的自定义用户模型存在问题.我在apps.users.AuthUser中声明了自定义用户模型.然后,我有了另一个应用程序(apps.pets),该应用程序将AuthUser用作Pet模型中的ForeignKey.见下文:

I am having problems with my custom user model while using Django 1.7.1 and Python 3.4. I have declared a Custom user model in an apps.users.AuthUser. I then have another application (apps.pets) that will use the AuthUser as a ForeignKey in a Pet model. See below:

class Pet(models.Model):
    owner = models.ForeignKey(settings.AUTH_USER_MODEL, db_index=True, blank=False, null=False)

这是我的情况:

在我的 INSTALLED_APPS 中,我有:"apps.users"

In my INSTALLED_APPS I have: "apps.users"

如果我设置 AUTH_USER_MODEL ="apps.users.AuthUser" ,则在运行"runserver"时会引发异常:

If I set AUTH_USER_MODEL="apps.users.AuthUser" the exception is raised when I run 'runserver':

File "/home/frank/.virtualenvs/myproj/lib/python3.4/site-packages/django/contrib/auth/checks.py", line 12, in check_user_model
    cls = apps.get_model(settings.AUTH_USER_MODEL)
  File "/home/frank/.virtualenvs/myproj/lib/python3.4/site-packages/django/apps/registry.py", line 201, in get_model
    app_label, model_name = app_label.split('.')
ValueError: too many values to unpack (expected 2)

如果我设置AUTH_USER_MODEL ="users.AuthUser",则在运行迁移时会引发异常:

If I set AUTH_USER_MODEL="users.AuthUser" the exception is raised when I run migrate:

File "/home/frank/.virtualenvs/myproj/lib/python3.4/site-packages/django/db/migrations/state.py", line 89, in render
    model=lookup_model,
ValueError: Lookup failed for model referenced by field pets.Pet.owner: users.AuthUser

我在这里报告了类似的问题: https://code.djangoproject.com/ticket/19845

Similar issue reported here I guess: https://code.djangoproject.com/ticket/19845

这是否意味着在 AUTH_USR_MODEL 设置中,我必须使用"app_label.model_name"而不是"apps.app_label.model_name"?有解决方法吗?

Does this mean that in AUTH_USR_MODEL setting I have to use 'app_label.model_name' instead of 'apps.app_label.model_name.'? Is there a workaround for this?

我的项目结构如下:

SITE_ROOT
|-- PROJECT_ROOT/
|   |-- apps/
|   |   |-- app1
|   |   |-- app2
|   |-- etc/
|   |-- libs/
|   |-- media/
|   |-- requirements/
|   |   |-- __init__.py
|   |   |-- common.py
|   |   |-- development.py
|   |   |-- production.py
|   |   `-- staging.py
|   |-- settings/
|   |   |-- __init__.py
|   |   |-- common.py
|   |   |-- development.py
|   |   |-- production.py
|   |   `-- staging.py
|   |-- templates/
|   |-- README
|   |-- __init__.py
|   |-- .gitignore
|   `-- manage.py

推荐答案

在已安装的应用程序中,您可以仅假设应用程序名称位于相同目录中,而无需特别提及"myapp.users",而只需"myapp"即可做.

In your installed apps you can have just your application name assuming its in the same directory, no need to specifically mention 'myapp.users' just 'myapp' will do.

使用此:

AUTH_USER_MODEL = 'myapp.MyAuthUserModel'

请勿使用此功能:

AUTH_USER_MODEL = 'myapp.models.MyAuthUserModel'

希望这会有所帮助!

这篇关于AUTH_USER_MODEL不接受子申请的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆