如何将图像传递给python中的request.post? [英] How to pass image to requests.post in python?

问题描述

对不起，我是Django的新手，我对图像上传感到困惑.

Sorry Guys, I am new to Django, I am stuck with images upload.

我有一个用于上传图片的REST_API.我传递图像，并在API内部通过使用获得该图像 request.FILES ['fileToUpload'] .

I have a REST_API for image upload. I pass the image and inside API get that image by using request.FILES['fileToUpload'].

现在，我有一个外部API，该API代表我上传了一个图像，该API在邮递员上正常工作.

Now I have an external API, which uploads an image on my behalf, that API is working fine on the postman.

这是该API的路径.

http://164.68.110.65/file_load.php

但是在Django中.我无法将图片传递给此API.我尝试了很多方法.

But in Django. I am not able to pass the image to this API. I have tried many ways.

像这些.

 image = request.FILES['fileToUpload']
 temp = Image.open(image)
 byte_io = BytesIO()
 temp.save(byte_io, 'png')
 files = {'fileToUpload': byte_io.getvalue() }
 response = requests.post( self.URL, files=files)
 print(response.status_code, response.content, response.reason)

但是它总是给我一个错误，指出图像格式不匹配.

but it always giving me an error that image format is not matched.

您能否在python请求中告诉我，我们应该如何传递我的 request.FILES ['file_name_any'] 中获得的图像或文件.

can you please tell me, in python-requests, how we should pass images or files that are got my request.FILES['file_name_any'].

谢谢.我将非常感谢您的光临.

Thanks. I will be very thankful for your favor.

推荐答案

您的 image 是 UploadedFile 或 TemporaryUploadedFile 是子类 File .因此，您通常可以将 .open()用作其他任何 File 对象:

Your image is an UploadedFile or a TemporaryUploadedFile which is a subclass of File. So you can just .open() it normally as any other File object:

with image.open('rb') as f:
    files = {'fileToUpload': f}
response = requests.post(self.URL, files=files)

无需先走弯路，先保存文件.

No need to take the detour through saving the file first.

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