XPath表达式按源顺序选择*所有*元素，文本节点和注释节点 [英] XPath expression to select *all* elements, text nodes, and comment nodes in source order

问题描述

按什么顺序选择所有元素，文本节点和注释节点的XPath表达式是什么?

What’s the XPath expression to select all elements, text nodes, and comment nodes, in the same order as they appear in the document?

以下内容有效地选择了所有元素，但没有选择文本节点和注释节点:

The following effectively selects all elements, but not text nodes and comment nodes:

var result = document.evaluate('//*', document, null, XPathResult.ORDERED_NODE_SNAPSHOT_TYPE, null),
    index = -1;
while (++index < result.snapshotLength) {
  console.log(result.snapshotItem(index));
}

是否可以执行以下操作?(注意:这是无效的伪代码.)

Is it possible to do something like the following? (Note: this is non-functional pseudo-code.)

document.evaluate('//* and text() and comment()');

推荐答案

//node()

选择所有子节点，即所有元素，文本节点，注释和处理指令(但不选择属性，名称空间节点或文档节点)

selects every node that is a child of something: i.e all elements, text nodes, comments, and processing instructions (but not attributes, namespace nodes, or the document node)

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