Android用Java唤醒Lan [英] Android Wake On Lan in Java

问题描述

我正在尝试使用Java(适用于Android)制作Wake On Lan应用程序，因此我进行了搜索，并找到了以下代码:

i'm trying to make a Wake On Lan application in Java (for Android), so I searched, and found this code:

import java.io.*;
import java.net.*;

public class WakeOnLan {

public static final int PORT = 9;    

public static void main(String[] args) {

    if (args.length != 2) {
        System.out.println("Usage: java WakeOnLan <broadcast-ip> <mac-address>");
        System.out.println("Example: java WakeOnLan 192.168.0.255 00:0D:61:08:22:4A");
        System.out.println("Example: java WakeOnLan 192.168.0.255 00-0D-61-08-22-4A");
        System.exit(1);
    }

    String ipStr = args[0];
    String macStr = args[1];

    try {
        byte[] macBytes = getMacBytes(macStr);
        byte[] bytes = new byte[6 + 16 * macBytes.length];
        for (int i = 0; i < 6; i++) {
            bytes[i] = (byte) 0xff;
        }
        for (int i = 6; i < bytes.length; i += macBytes.length) {
            System.arraycopy(macBytes, 0, bytes, i, macBytes.length);
        }

        InetAddress address = InetAddress.getByName(ipStr);
        DatagramPacket packet = new DatagramPacket(bytes, bytes.length, address, PORT);
        DatagramSocket socket = new DatagramSocket();
        socket.send(packet);
        socket.close();

        System.out.println("Wake-on-LAN packet sent.");
    }
    catch (Exception e) {
        System.out.println("Failed to send Wake-on-LAN packet: + e");
        System.exit(1);
    }

}

 private static byte[] getMacBytes(String macStr) throws IllegalArgumentException {
    byte[] bytes = new byte[6];
    String[] hex = macStr.split("(\\:|\\-)");
    if (hex.length != 6) {
        throw new IllegalArgumentException("Invalid MAC address.");
    }
    try {
        for (int i = 0; i < 6; i++) {
            bytes[i] = (byte) Integer.parseInt(hex[i], 16);
        }
    }
        catch (NumberFormatException e) {
        throw new IllegalArgumentException("Invalid hex digit in MAC address.");
    }
    return bytes;
}


}

我在PC上尝试了它，但它在Android上不起作用:(我试图对其进行编辑，但仍然没有效果:(这是我在Android上的代码:

I tried it on my PC, it worked, but it doesn't work for Android :( I tried to edit it, but still nothing :( Here's my code for Android:

import java.net.DatagramPacket;
import java.net.DatagramSocket;
import java.net.InetAddress;

import com.macura.wakemypc.MainActivity;

import com.macura.wakemypc.R;
import com.macura.wakemypc.MainActivity;

import com.macura.wakemypc.MainActivity;

import android.os.Bundle;
import android.app.Activity;
import android.view.Menu;
import android.view.View;
import android.widget.EditText;

public class MainActivity extends Activity {
public static final int PORT = 9;    





@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.main, menu);
    return true;
}
public void buttonClick(View view) {
    EditText iptext = (EditText)findViewById(R.id.editText1);
    EditText mactext = (EditText)findViewById(R.id.editText2);
    String mac = mactext.toString();
    String broadcastIP = iptext.toString();
    MainActivity.wakeup(broadcastIP, mac);
 }
private static byte[] getMacBytes(String mac) throws IllegalArgumentException {
    // TODO Auto-generated method stub
    byte[] bytes = new byte[6];
    if (mac.length() != 12)
    {
        throw new IllegalArgumentException("Invalid MAC address...");
    }
    try {
        String hex;
        for (int i = 0; i < 6; i++) {
            hex = mac.substring(i*2, i*2+2);
            bytes[i] = (byte) Integer.parseInt(hex, 16);
        }
    }
    catch (NumberFormatException e) {
        throw new IllegalArgumentException("Invalid hex digit...");
    }
    return bytes;
}

public static void wakeup(String broadcastIP, String mac) {
    if (mac == null) {
        return;
    }

        try {
            byte[] macBytes = getMacBytes(mac);
            byte[] bytes = new byte[6 + 16 * macBytes.length];
            for (int i = 0; i < 6; i++) {
                bytes[i] = (byte) 0xff;
            }
            for (int i = 6; i < bytes.length; i += macBytes.length) {
                System.arraycopy(macBytes, 0, bytes, i, macBytes.length);
            }

            InetAddress address = InetAddress.getByName(broadcastIP);
            DatagramPacket packet = new DatagramPacket(bytes, bytes.length, address, 5555);
            DatagramSocket socket = new DatagramSocket();
            socket.send(packet);
            socket.close();



        }
        catch (Exception e) {
    }

}
}

每次我输入ip和mac地址时，它什么都不做.所以，能帮我吗?:)是的，对不起我的英语:D

Everytime I enter the ip and mac adress it does nothing. So, can you help me, please? :) Yeah, and sorry for my english :D

推荐答案

我对其余的代码并不确定，但是您应该使用 String mac = mactext.getText().toString(); 而不是 String mac = mactext.toString(); 导致，如果不进行此更改，您将转换为整个整个EditText字符串，而不仅仅是其值.P.S.我知道问题十个月后，仍然对于任何会来这里寻找WOL android代码的人来说都是有用的

I'm not shure about rest of the code, but you should use String mac = mactext.getText().toString(); instead of String mac = mactext.toString(); cause without this change you converting to string entire EditText not just its value. P.S. i know its 10 months after question, still for anyone who would come here looking for WOL android code it should be usefull

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