基于长度,空格,"/"或"EXCEL"的EXCEL VBA超过3行的字符串长度_"人物 [英] EXCEL VBA String length over 3 lines based on length , spaces, "/", or " _" characters
问题描述
基于Zac在
我现在需要对其进行更新,以包括以下可能性:文本/单词不能用空格分隔,而不能用字符"/"或"_"分隔.我的小提琴没有成功.我在函数中添加了if语句,例如:-
I now need to update to it to include the possibility that the text/words may not be separated by spaces but also the characters "/" or "_". I've had a good fiddle without success. I added if statements to the function such as :-
If InStr(55, sText, "_") > 0 Then
sGreater55 = Mid(sText, InStr(55, sText, "_"))
没有成功:-(
Function SetString(ByVal sText As String) As String
Dim sGreater55$, sGreater19$
'如果文本大于55个字符,则首先让我们捕获55个字符之后的字符串(取决于SPACE字符的位置)
' If text is greater than 55 characters, first lets capture the string after 55 characters (depending on where the SPACE character is)
If Len(sText) > 55 Then
If InStr(55, sText, " ") > 0 Then
sGreater55 = Mid(sText, InStr(55, sText, " "))
Else
sGreater55 = Mid(sText, InStrRev(sText, " ", 55))
End If
End If
'如果文本大于19个字符,则让我们在19个字符之后构建字符串(取决于SPACE字符的位置)
' If text is greater than 19 characters, lets build the string after 19 characters (depending on where the SPACE character is)
If Len(sText) > 19 Then
If InStr(19, sText, " ") > 0 Then
sGreater19 = Mid(sText, InStr(19, sText, " "))
Else
sGreater19 = Mid(sText, InStrRev(sText, " ", 19))
End If
sGreater19 = Left(sGreater19, Len(sGreater19) - Len(sGreater55))
End If
'现在让我们构建完整的字符串
' Now lets build the complete string
SetString = Left(sText, Len(sText) - (Len(sGreater19) + Len(sGreater55))) & vbLf & sGreater19 & vbLf & sGreater55
End Function
推荐答案
假定 split 字符可能混合在一起(例如, blah_blah_blah blah_blah/blahblah
:创建输入字符串的副本,将所有可能的 split 字符替换为空白并轻松修改函数:
Assuming that there might be an mixture of the split characters (Eg blah_blah_blah blah_blah/blahblah
: Create a copy of your input string, replace all possible split characters by blank and slighly modify the function:
Function SetString(ByVal sText As String) As String
Dim sGreater55$, sGreater19$
Dim sTextCopy As String
sTextCopy = Replace(Replace(sText, "/", " "), "_", " ")
' If text is greater than 55 characters, first lets capture the string after 55 characters (depending on where the SPACE character is)
If Len(sText) > 55 Then
If InStr(55, sText, " ") > 0 Then
sGreater55 = Mid(sText, InStr(55, sTextCopy, " "))
Else
sGreater55 = Mid(sText, InStrRev(sTextCopy, " ", 55))
End If
End If
' If text is greater than 19 characters, lets build the string after 19 characters (depending on where the SPACE character is)
If Len(sText) > 19 Then
If InStr(19, sText, " ") > 0 Then
sGreater19 = Mid(sText, InStr(19, sTextCopy, " "))
Else
sGreater19 = Mid(sText, InStrRev(sTextCopy, " ", 19))
End If
sGreater19 = Left(sGreater19, Len(sGreater19) - Len(sGreater55))
End If
' Now lets build the complete string
SetString = Left(sText, Len(sText) - (Len(sGreater19) + Len(sGreater55))) & vbLf & sGreater19 & vbLf & sGreater55
End Function
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