在C ++ 11中继承异常? [英] Inheriting Exceptions in C++11?

问题描述

我有一个名为 Matrix< t> 的类，我的教授要求我编写一个异常类:

I have a class called Matrix<t>, My professor asked me to write an exception class:

Matrix::IllegalInitialization

它包含功能 what()，所以我写了(在Matrix.h中):

Such that it includes the function what(), So I wrote (In Matrix.h):

template<class T>
class Matrix<T>::IllegalInitialization {
public:
    std::string what() const {
        return "Mtm matrix error: Illegal initialization values";
    }
};

但是我有一个问题，该类不能继承Exception，如何解决此问题?

But I have a problem that this class doesn't inherit Exceptions, how to fix this?

我要执行以下操作:

     try {
         Dimensions dim(0,5);
         Matrix<int> mat(dim);
} catch (const mtm::Matrix<int>::IllegalInitialization & e){ cout<< e.what() <<endl;
}

---

修改:这是我的代码的样子吗?

---

Is this how should my code look like?

template<class T>
class Matrix<T>::IllegalInitialization : public std::exception {
public:
   const char* what() const override {
      return "Mtm matrix error: Illegal initialization values";
   }
};

我得到了:

错误:覆盖函数的异常说明比基本版本更宽松

error: exception specification of overriding function is more lax than base version

推荐答案

std :: exception 的 what()方法为(cf

The what() method of std::exception is (cf cppreference):

virtual const char* what() const noexcept;

您的方法未声明为 noexcept ，因此无法覆盖 std :: exception :: what().

Your method is not declared noexcept hence it cannot override std::exception::what().

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