从node.js运行Python脚本时发生parseError [英] parseError when running Python script from node.js
问题描述
我正在构建电影推荐器.我的推荐器引擎是用Python编写的.而且我正在通过node.js(Express)在网站上运行它.
I am constructing a movie recommender. My recommender engine is written in Python. And I am running it from website through node.js (Express).
python代码本身起作用,这是我从控制台运行它时的输出.它使用pandas和numpy进行计算,它返回一个矩阵,该矩阵包含电影的标题及其与所选电影的相似性,并且我还会打个招呼:
The python code itselfs work and here is the output when I am running it from a console. It is using pandas and numpy for calculations it returns a matrix with title of movie and its similarity to a chosen movie, and I also print hello:
在我的网站上,我的正文中包含 HTML :
On my website I have following HTML in body:
<form class="test" method="post" action="/test">
<input type="text" name="user[name]">
<input class="button" type="submit" value="Submit">
</form>
JS 客户端
(function($) {
$(document).ready(function () {
var btn = $('.button'),
input = $('input');
btn.on('click', function() {
e.preventDefault();
})
})
})(jQuery)
JS 服务器端,带有 Express
var express = require('express');
var app = express();
var path = require('path');
var bodyParser = require('body-parser');
var PythonShell = require('python-shell');
var options = {
mode: 'text',
pythonOptions: ['-u'],
scriptPath: "E:/Praca Magisterska/Python",
};
app.use(express.static(path.join(__dirname, '')));
app.use(bodyParser.json());
app.use(bodyParser.urlencoded({
extended: true
}));
app.get('/', function (req, res) {
res.sendFile(path.join(__dirname+'/index.html'));
})
app.post('/test', function (req, res) {
console.log(req.body);
PythonShell.run('similarMovies.py', options, function (err, results) {
if (err) throw err;
// results is an array consisting of messages collected during execution
console.log('results: %j', results);
});
})
app.listen(3000, function () {
console.log('Example app listening on port 3000!');
})
所以,它是如何工作的.单击提交btn时,我启动了node.js来运行python脚本,然后 console.log
结果.不幸的是,我得到了错误,最后是图片.
So, how it works. On clicking submit btn I am firing my node.js to run a python script and then console.log
the results. Unfortunately I am getting errors, image at the end.
但是,当我不运行函数而不是运行函数时,我只是在Python的末尾编写了代码:
However, when I do not run function and instead of it I write at the end of my Python just:
print "hello"
print 2
代码结果解析良好.
可能是个问题?我在函数中除以零和其他除法得到的错误?但是,如果是为什么,那么当我直接从cmd运行它时它会起作用- python likeMovies.py
What could be an issue? Erros that I am getting with dividing by zero and other inside a funcion? But if yes why then it is working when I run it directly from cmd - python similarMovies.py
这是 python 代码:
# -*- coding: utf-8 -*-
import pandas as pd
import numpy as np
def showSimilarMovies(movieTitle, minRatings):
# import ratingów z pliku csv
rating_cols = ['user_id', 'movie_id', 'rating']
rating = pd.read_csv('E:/Praca Magisterska/MovieLens Data/ratings.csv', names = rating_cols, usecols = range(3))
# import filmów z pliku csv
movie_cols = ['movie_id', 'title']
movie = pd.read_csv('E:/Praca Magisterska/MovieLens Data/movies.csv', names = movie_cols, usecols = range(2))
# łączenie zaimportowanych ratingów oraz filmów, usuwanie pierwszego wiersza
ratings = pd.merge(movie, rating)
ratings = ratings.drop(ratings.index[[0]])
# konwertowanie kolumn ze stringów na numeric
ratings['rating'] = pd.to_numeric(ratings['rating'])
ratings['user_id'] = pd.to_numeric(ratings['user_id'])
# tworzenie macierzy pokazująceje oceny filmów przez wszystkich użytkowników.
movieRatingsPivot = ratings.pivot_table(index=['user_id'], columns=['title'], values='rating')
# filtrowanie kolumny do obliczania filmów podobnych
starWarsRating = movieRatingsPivot[movieTitle]
# obliczanie korelacji danego filmu z każdym innym i wyrzucanie tych z którymi nic go nie łączy
similarMovies = movieRatingsPivot.corrwith(starWarsRating)
similarMovies = pd.DataFrame(similarMovies.dropna())
# zmiana nazwy kolumny oraz sortowanie według rosnącej korelacji
similarMovies.columns = ['similarity']
similarMovies.sort_values(by=['similarity'], ascending=False)
# tworzenie statystyk dla filmów, size to ilość ocen, a mean to średnia z ocen
# zgrupowane po tytułach
movieStats = ratings.groupby('title').agg({'rating': [np.size, np.mean]})
# popularne filmy, które mają więcej niż 100 ocen
popularMovies = movieStats['rating']['size']>=minRatings
# sortowanie popularnych filmów od najwyższej średniej
movieStats[popularMovies].sort_values(by=[('rating', 'mean')], ascending=False)
# łączenie popularnych filmów z filmami podobnymi do filtrowanego filmu i ich sortowanie
moviesBySimilarity = movieStats[popularMovies].join(similarMovies)
x = moviesBySimilarity.sort_values(by='similarity', ascending=False)
k = x.drop(x.columns[[0, 1]], axis = 1)
k = k.drop(x.index[[0]])
return k
print "hello"
print 2
showSimilarMovies('Star Wars: Episode VI - Return of the Jedi (1983)', 300)
推荐答案
我知道了,只是在python文件的开头添加了两行来忽略警告:
I figured it out, just added two lines at the beggining of python file to ignore warnings:
import warnings
warnings.filterwarnings('ignore')
现在我的输出是所需的.
Now my output is what was desired.
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