scalax.io._覆盖文件中数据的最佳方法 [英] scalax.io._ Best way to overwrite data in file

问题描述

我发现，对scalax.io._中的文件进行写操作的默认方式是追加".但是，与Resource.fromFile对象一起操作以重写诸如系统IO open(..，WRITE)调用之类的数据的最佳和最短方法是什么?我的想法是删除文件或使用seek/patching API.但对于这种简单的操作，他们会很冗长.

I have found that default way in write operations on file in scalax.io._ is "append". But what the best and shortest way to operate with Resource.fromFile object for ovewriting data like system IO open(..,WRITE) call ? The Ideas that i have are deleting file or using seeking/patching API . but they to verbose for such simple operation .

scala> def mk(s:String) = { val out: Output = Resource.fromFile("/tmp/data");out.write(s)}
mk: (s: String)Unit

scala> mk("XXXX")
scala> mk("XXXX")

bash# > ls -l /tmp/data

-rw-rw-r-- 1 root root 8 Jun  1 16:27 /tmp/data

推荐答案

使用普通的旧输出流:

import scalax.io.Resource
import scalax.io._
val out:Output = Resource.fromOutputStream(new java.io.FileOutputStream("/tmp/testFile"))


out write "howdy"
out write "bah"

请小心，因为每次写入都会重写文件.请参阅每日scala 如何解决此问题，以及有关更多示例

Be careful as file will be rewritten on each write. See daily scala how to overcome this, and for more examples

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