Python从列表中过滤/删除URL [英] Python filter/remove URLs from a list

问题描述

我有一个约14000的URL文本文件.下面是几个示例:

I have a text file of URLs, about 14000. Below is a couple of examples:

http://www.domainname.com/pagename?CONTENT_ITEM_ID=100&; param2 = 123
http://www.domainname.com/images?IMAGE_ID=10
http://www.domainname.com/pagename?CONTENT_ITEM_ID=101&param2=123
http://www.domainname.com/images?IMAGE_ID=11
http://www.domainname.com/pagename?CONTENT_ITEM_ID=102&param2=123

http://www.domainname.com/pagename?CONTENT_ITEM_ID=100&param2=123
http://www.domainname.com/images?IMAGE_ID=10
http://www.domainname.com/pagename?CONTENT_ITEM_ID=101&param2=123
http://www.domainname.com/images?IMAGE_ID=11
http://www.domainname.com/pagename?CONTENT_ITEM_ID=102&param2=123

我已将文本文件加载到Python列表中，并且试图将所有具有CONTENT_ITEM_ID的URL分离到它们自己的列表中.用Python做到这一点的最佳方法是什么?

I have loaded the text file into a Python list and I am trying to get all the URLs with CONTENT_ITEM_ID separated off into a list of their own. What would be the best way to do this in Python?

欢呼

推荐答案

这是Graeme的另一种替代方法，它使用了较新的列表理解语法:

Here's another alternative to Graeme's, using the newer list comprehension syntax:

list2= [line for line in file if 'CONTENT_ITEM_ID' in line]

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Which you prefer is a matter of taste!

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