如何将根路径与扭曲过滤器匹配? [英] How can I match the root path with a Warp filter?

问题描述

我有一个使用Warp的简单Web服务器，该服务器提供静态文件.我遵循了Warp文档中的示例以获取以下信息:

 让index_html = warp :: path(" index.html").map(handlers :: index_html);//回复在`handlers ::`中处理让script_js = warp :: path("script.js").map(handlers :: script_js);让路由= warp :: get().and(index_html.or(script_js));warp :: serve(routes).run(([127，0，0，1]，8000)).await; 

当从 localhost:8000/index.html 和 localhost:8000/script.js 请求时，此文件返回文件.

我想从 localhost:8000 提供索引文件，而不是从/index.html 提供索引文件，但是我不确定如何使用指定域根目录> warp :: path .我尝试用

替换 warp :: path(" index.html")

• warp :: path()
• warp :: path("")
• warp :: path("/")

但没有成功.

解决方案

要定位根路径，请使用 warp :: path :: end().文档的描述含糊不清.

对于上面的示例， index_html 的代码将替换为:

 让index_html = warp :: path :: end().map(...); 

I have a simple web server using Warp that serves static files. I followed the examples in the Warp docs to get the following:

let index_html = warp::path("index.html").map(handlers::index_html); // reply is handled in `handlers::`

let script_js = warp::path("script.js").map(handlers::script_js);

let routes = warp::get().and(index_html.or(script_js));

warp::serve(routes).run(([127, 0, 0, 1], 8000)).await;

This returns files when requested from localhost:8000/index.html and localhost:8000/script.js.

I want to serve the index file from localhost:8000 rather than /index.html, but I'm not sure how to specify the domain root with warp::path. I've tried replacing warp::path("index.html") with

• warp::path()
• warp::path("")
• warp::path("/")

but with no success.

解决方案

To target the root path use warp::path::end(). The docs have an ambiguously brief description.

For the example above the code for index_html would be replaced with:

let index_html = warp::path::end().map( ... );

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